Even when you cannot prevent a collision, braking can help slow your car down before it collides with another car.
How will the speed of a vehicle at the moment of first contact in a collision affect the outcomes?
In your notebook, predict how you think speed will affect collision outcomes (what happens after a collision) and explain your reasoning.
In real-world collisions, slowing down a vehicle before impact can significantly change the outcomes. This lesson explores how speed affects collisions using scaled-down models that allow us to observe and measure these effects safely.
Let’s observe three different collisions between two carts and notice what happens in each case.
Copy the table below into your science notebook. In the table, make quick before and after sketches of the three collision scenarios A, B, and C. An example “before” sketch is provided for you. Use labelled arrows to show velocities before and after. Direction can be shown for final/”after” velocities even if the values are not known.
Collision | Before | After | Notes |
---|---|---|---|
A | ![]() |
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B | |||
C |
Activity: As you watch the video, observe:
What is happening during these collisions that is causing the yellow-yellow cart (left) to slow down and the blue cart (right) to speed up? Write your initial explanation in your notebook.
Remember our previous unit where we developed a model showing how energy transfer from one object/system to another was the result of force interactions.
Since the carts make contact for a relatively brief period of time during a collision, let’s consider a forces perspective and think about how the contact forces between the two cars during that time could help explain the outcomes we observed.
If we could measure the contact force(s) between the carts during the collision, how would we expect they would compare?
Consider these possibilities:
Make your prediction before continuing. What evidence do you have for your prediction?
It is suggested that you copy the following notes into your science notebook for future reference.
To get more insights about what’s happening during the brief moment of collision, we need special sensors that can collect force and velocity data before, during, and after a collision.
Now let’s analyze how the speeds of the carts changed during the collisions.
Data Analysis: Study the force graphs for all three collisions and write your answers to the following prompts in your Science Notebook.
In the data, we noticed that the force measured on the yellow cart is negative while the force measured on the blue cart is positive.
What does the sign of the force tell us?
Remember that force is a vector quantity with both magnitude and direction:
Using this understanding we see why the forces on the two carts have opposite signs during collision.
Data Analysis: Study the speed graphs for all three collisions. You may wish to sketch their shapes into your notebook. Consider:
- How do the speeds change during collision?
- Compare the speed changes between collisions A, B, and C
- What patterns do you notice?
In collision C, we noticed that the initial speed of the yellow cart is negative before the collision, and the blue cart has a negative speed after the collision.
Analyzing the meaning of negative velocity:
Now let’s explore how changing the mass of the carts affects collision outcomes.
Copy the table below int your Science Notebook. Draw the experimental setup (as before) in the “before” column but for the new situations. Sketch your predictions in the middle column. Finally, record your observations in the final column after viewing the collisions.
Make Predictions: For each scenario, predict how changing mass will affect the force and velocity outcomes:
Collision | Before | After (Prediction) |
After (Observed) |
---|---|---|---|
D Double the mass of both carts |
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E Double the mass of the yellow (left) cart only |
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F Double the mass of the blue (right) cart only |
Now let’s see what actually happens in these different mass scenarios.
How does mass affect the forces on each object in a collision? How does mass affect the change in velocity of each object in a collision?
Add terms below to make statements based on the data. Based on our data analysis, we can make two key observations:
- Increases in mass in the system resulted in ________ in the magnitude of the forces
- When masses are unequal in a collision, the ________ mass changes velocity more than the ________ mass
Let’s examine the precise mathematical relationship between mass and velocity changes in our collisions.
Let’s organize the velocity measurements for Collisions E and F.
Copy the table below into your science notebook. Then, add the mathematical relationship shown beneath it.
Collision | Cart | Mass (kg) | Initial Velocity (m/s) | Final Velocity (m/s) | Change in Velocity (m/s) |
---|---|---|---|---|---|
E | Yellow | 0.6 | 0.79 | 0.33 | -0.46 |
E | Blue | 0.3 | 0 | 0.92 | 0.92 |
F | Yellow | 0.3 | 0.8 | -0.12 | -0.92 |
F | Blue | 0.6 | 0 | 0.46 | 0.46 |
These data show us how changing mass affects the velocity outcomes in collisions, which we’ll analyze mathematically below.
The data reveal that:
$\frac{m_1}{m_2} = -\frac{\Delta v_2}{\Delta v_1}$
In other words, the ratio of masses equals the negative reciprocal of the ratio of velocity changes. This means when one object has twice the mass of another, its velocity change will be half as large (and in the opposite direction).
Let’s calculate the velocity changes for Collision E:
For the yellow cart (double mass):
$\Delta v_{\text{yellow}} = v_{\text{final}} - v_{\text{initial}} = 0.33 \text{ m/s} - 0.79 \text{ m/s} = -0.46 \text{ m/s}$
For the blue cart (normal mass):
$\Delta v_{\text{blue}} = v_{\text{final}} - v_{\text{initial}} = 0.92 \text{ m/s} - 0 \text{ m/s} = 0.92 \text{ m/s}$
Ratio of velocity changes:
$\frac{\Delta v_{\text{yellow}}}{\Delta v_{\text{blue}}} = \frac{-0.46 \text{ m/s}}{0.92 \text{ m/s}} = -0.5$
Ratio of masses:
$\frac{m_{\text{yellow}}}{m_{\text{blue}}} = \frac{2m}{m} = 2$
Checking our relationship:
$\frac{m_{yellow}}{m_{blue}} = \frac{0.6 \mathrm{kg}}{0.3 \mathrm{kg}} = 2$
$-\frac{\Delta v_{\text{blue}}}{\Delta v_{\text{yellow}}} = -\frac{0.92}{-0.46} = 2$
The relationship is verified!
Let’s apply our mathematical relationship to real-world situations. Copy these sample problems into your science notebook and solve them as reference examples.
Example 1: A large truck (20,000 kg) collides with a stationary shopping cart (20 kg). How will their velocity changes compare?
Using our relationship $\frac{m_1}{m_2} = -\frac{\Delta v_2}{\Delta v_1}$, calculate:
Ratio of masses:
$\frac{m_{\text{truck}}}{m_{\text{cart}}} = \frac{20,000 \text{ kg}}{20 \text{ kg}} = 1,000$
The ratio of velocity changes you would expect
Expected ratio of velocity changes:
$\frac{m_{\text{truck}}}{m_{\text{cart}}} = -\frac{\Delta v_{\text{cart}}}{\Delta v_{\text{truck}}}$
$1,000 = -\frac{\Delta v_{\text{cart}}}{\Delta v_{\text{truck}}}$
$\frac{\Delta v_{\text{cart}}}{\Delta v_{\text{truck}}} = -1,000$
If truck’s velocity decreases by 0.01 m/s:
$\Delta v_{\text{truck}} = -0.01 \text{ m/s}$
$\frac{\Delta v_{\text{cart}}}{-0.01 \text{ m/s}} = -1,000$
$\Delta v_{\text{cart}} = -0.01 \text{ m/s} \times (-1,000) = 10 \text{ m/s}$
The shopping cart’s velocity would increase by 10 m/s (about 22 mph)!
This helps explain why in collisions between vehicles of very different masses (like a truck and a car), the smaller vehicle experiences much more dramatic changes in velocity—which directly relates to safety outcomes for the occupants.
Answer these questions on a half sheet of paper and turn it in at the end of class.