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Giancoli 7th Ed. Aligned

Honors Physics > Unit 2: Circular Motion > Uniform Circular Motion

centripetal accelerationuniform circular motiongiancoli

title: "Uniform Circular Motion" course: "honors-physics" unitSlug: "unit-2-circular-motion" topicSlug: "uniform-circular-motion" tags:

  • "centripetal acceleration"
  • "uniform circular motion"
  • "giancoli" chapter: 5 giancoliRef: "7th Ed. Chapter 5, Section 1-3"

Uniform Circular Motion

An object moving in a circle of radius rr at a constant speed vv is undergoing uniform circular motion.

Even though the speed is constant, the velocity vector v\vec{v} continuously changes direction. Therefore, the object experiences a centripetal acceleration ac\vec{a}_c directed toward the center.

ac=v2rr^\vec{a}_c = \frac{v^2}{r} \hat{r} Centripetal acceleration vector equals velocity squared divided by radius, in the radial direction.

Concept Focus

In this topic, students should be able to:

  • Explain why constant speed can still produce acceleration.
  • Identify the direction of centripetal acceleration.
  • Use ac=v2ra_c = \frac{v^2}{r} to solve circular motion problems.

Sample Problem (Giancoli Ch. 5)

A 1,200 kg1{,}200\text{ kg} car rounds a flat curve of radius r=65 mr = 65\text{ m} on a wet road with coefficient of static friction μs=0.25\mu_s = 0.25.

  1. Radial force requirement: Ff=mv2rF_f = m \frac{v^2}{r}
  2. Maximum friction: Ff=μsFN=μsmgF_f = \mu_s F_N = \mu_s mg
  3. Equate and solve:

v=μsgrv = \sqrt{\mu_s g r} Speed equals the square root of static friction coefficient times gravity times radius.

v=(0.25)(9.8 m/s2)(65 m)12.6 m/sv = \sqrt{(0.25)(9.8\text{ m/s}^2)(65\text{ m})} \approx 12.6\text{ m/s} Substituting values gives a safe speed of approximately 12.6 meters per second.

Reflection Prompt

If the road condition changes and μs\mu_s decreases, what must happen to the safe speed and why?